Ss bhavikatti engineering mechanics solutions pdf

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Problems & Solutions In Engineering Mechanics book. Read 7 reviews from the world's largest community for readers. Each chapter begins with a quick discu. May 30, Problems and Solutions in Engineering Mechanics by S. S. Bhavikatti, , available at Book Depository with free delivery. Problems and Solutions in Engineering Mechanics by S.S. Bhavikatti, A. Vittal Hegde starting at $ Problems and Solutions in Engineering Mechanics has .

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Ss Bhavikatti Engineering Mechanics Solutions Pdf

Download Engineering Mechanics By S.S. Bhavikatti – This is a comprehensive book meeting complete requirements of Engineering Mechanics Course of. download Problems and Solutions in Engineering Mechanics by S. S. Bhavikatti, A. Vittal Hegde from Waterstones today! Click and Collect from your local. Engg Mechanics - Download as Word Doc .doc /.docx), PDF File .pdf), Text File .txt) or Problems & Solutions In Engineering Mechanics - S. S. Bhavikatti.

No part of this ebook may be reproduced in any form, by photostat, microfilm, xerography,or any other means, or incorporated into any information retrieval system, electronic ormechanical, without the written permission of the publisher. All inquiries should beemailed to rights newagepublishers. In this course, laws of mechanics are appliedto parts of bodies and skill is developed to get solution to engineering problemsmaintaining continuity of the parts. The author has clearly explained theories involved and illustrated them bysolving a number of engineering problems. Neat diagrams are drawn andsolutions are given without skipping any step. SI units and standard notationsas suggested by Indian Standard Code are used throughout. The author hasmade this book to suit the latest syllabus of Gujarat Technical University. Author hopes, the students and teachers of Gujarat Technical University willreceive this book whole-heartedly as most of the earlier books of the authorhave been received by the students and teachers all over India. The suggestions and corrections, if any, are most welcome. New Age International Publish-ers in bringing out this book in nice form. Engineering College,Hubli. The branch of physicalscience that deal with the state of rest or the state of motion of bodies is termed as mechanics. Starting from the analysis of rigid bodies under gravitational force and application of simple forcesthe mechanics has grown into the analysis of complex structures like multistorey buildings, aircrafts,space crafts and robotics under complex system of forces like dynamic forces, atmospheric forcesand temperature forces. Archemedes — BC , Galileo — , Sir Issac Newton — and Einstein — have contributed a lot to the development of mechanics.

The successive event selected is the rotation ofearth about its own axis and this is called a day. To have convenient units for various activities,a day is divided into 24 hours, an hour into 60 minutes and a minute into 60 seconds. Clocks arethe instruments developed to measure time. To overcome difficulties due to irregularities in theearths rotation, the unit of time is taken as second which is defined as the duration of period of radiation of the cesium atom. SpaceThe geometric region in which study of body is involved is called space.

A point in the space maybe referred with respect to a predetermined point by a set of linear and angular measurements. Thereference point is called the origin and the set of measurements as coordinates.

If the coordinatesinvolved are only in mutually perpendicular directions, they are known as cartesian coordination. If the coordinates involve angles as well as the distances, it is termed as Polar Coordinate System. LengthIt is a concept to measure linear distances. The diameter of a cylinder may be mm, the heightof a building may be 15 m, the distance between two cities may be km.

Actually metre is the unit of length. However depending upon the sizes involved micro, milli or kilometre units are used for measurements. A metre is defined as length of the standard bar ofplatinum-iradium kept at the International Bureau of weights and measures.

Engineering Mechanics by S.S. Bhavikatti

To overcome thedifficulties of accessibility and reproduction now metre is defined as ContinuumA body consists of several matters. It is a well known fact that each particle can be subdividedinto molecules, atoms and electrons. It is not possible to solve any engineering problem by treatinga body as conglomeration of such discrete particles. The body is assumed to be a continuousdistribution of matter.

In other words the body is treated as continuum. In Fig.

After the application of forces F1, F2, F3, the body takes the position as shown in Fig. Theoretically speakingsuch a body cannot exist. However in dealing with problems involving distances considerably largercompared to the size of the body, the body may be treated as a particle, without sacrificingaccuracy.

For example: — A bomber aeroplane is a particle for a gunner operating from the ground. ForceForce is an important term used in solid mechanics. It states that the rate of change ofmomentum of a body is directly proportional to the impressed force and it takes place in thedirection of the force acting on it. In all the systems, unit of force is so selected that the constant of the proportionality becomesunity. For example, in S.

Characteristics of a ForceIt may be noted that a force is completely specified only when the 2m N Bfollowing four characteristics are specified C — Magnitude A — Point of application — Line of action Fig.

At point C, a personweighing N is standing. The force applied by the person on theladder has the following characters: — magnitude is N — the point of application is C which is at 2 m from A along the ladder — the line of action is vertical — the direction is downward.

It may be noted that in the figure — magnitude is written near the arrow — the line of arrow shows the line of application — the arrow head shows the point of application — the direction of arrow represents the direction of the force. The units of allother quantities may be expressed in terms of these basic units.

The systems are named after the units used to define the fundamental quantities length, massand time. Using these basic units, the units of other quantities can be found.

UnitsPresently the whole world is in the process of switching over to SI-system of units. As in MKS units in SI alsothe fundamental units are metre for length, kilogram for mass and second for time. As we have already seen one kg-wt is equal to 9.

The prefixes used in SI when quantities are too big or too small are shown in Table 1. Table 1. A quantity is saidto be scalar, if it is completely defined by its magnitude alone. Examples of scalars are length, area,time and mass. A quantity is said to be vector if it is completely defined only when its magnitude as well asdirection are specified. The example of vectors are displacement, velocity, acceleration, momentum,force etc. The resolution of vectors is exactly the oppositeprocess of composition i.

Parallelogram Law of VectorsThe parallelogram law of vectors enables us to determine the single vector called resultant vectorwhich can replace the two vectors acting at a point with the same effect as that of the two vectors. This law was formulated based on exprimental results on a body subjected to two forces. This lawcan be applied not only to the forces but to any two vectors like velocities, acceleration, momentumetc. Though stevinces employed it in , the credit of presenting it as a law goes to Varignonand Newton This law states that if two forcer vectors acting simultaneously on a bodyat a point are represented in magnitude and directions by the two adjacent sides of a parallelogram,their resultant is represented in magnitude and direction by the diagonal of the parallelogram whichpasses thorough the point of intersection of the two sides representing the forces vectors.

In the Fig. To get the resultant of these forces, according to this law, construct the parallelogramABCD such that AB is equal to 4 units to the linear scale and AC is equal to 3 units. Then accordingto this law, the diagonal AD represents the resultant in magnitude and direction.

Then AD shouldrepresent the resultant of F1 and F2. Thus we have derived the triangle law of forces from thefundamental law of parallelogram. The Triangle Law of Forces vectors may be stated as if twoforces vectors acting on a body are represented one after another by the sides of a triangle, theirresultant is represented by the closing side of the triangle taken from the first point to the last point. Polygon Law of Forces Vectors If more than two forces vectors are acting on a body, two forces vectors at a line can becombined by the triangle law, and finally resultant of all forces vectors acting on the body maybe obtained.

A system of four concurrent forces acting on a body are shown in Fig. Let it be called as R2. Thus we have derived the polygon law of the forces vectors and it may be statedas if a number of concurrent forces vectors acting simultaneously on a body are represented inmagnitude and direction by the sides of a polygon, taken in a order, then the resultant is representedin magnitude and direction by the closing side of the polygon, taken from the first point to the lastpoint.

Analytical Method of Composition of Two VectorsParallelogram law, triangle law and polygonal law of vectors can be used to find the resultantgraphically. This method gives a clear picture of the work being carried out. However the maindisadvantage is that it needs drawing aids like pencil, scale, drawing sheets.

Hence there is need foranalytical method. Drop perpendicular CE to AB. It may be noted that all component forces act at the same point as the given force.

Mechanics of Solids S.S. Bhavikatti

Resolutionof forces into its rectangular components is more useful in solving the problems in mechanics. Determine the resultant velocity of the boat. The guy wire of the electrical pole shown in Fig. Find the horizontal and vertical components of the force.

Determine its components normal to and parallel to the inclined plane. If AB represents thegiven force W to some scale, AC represents its component normal to the plane and CB representsits component parallel to the plane.

Imagine that the arrow drawn represents the given force to some scale. Travel from the tail to head of arrow in the direction of the coordinates selected. Then the direction of travel gives the direction of the component of vector.

From the triangle of vector, the magnitudes of components can be calculated. Example 1. The resultant of two forces, one of which is double the other is N. If the directionof the larger force is reversed and the other remain unaltered, the magnitude of the resultantreduces to N. Determine the magnitude of the forces and the angle between the forces.

Solution: Let the magnitude of the smaller force be F. Hence the magnitude of the larger force is2F. In this Fig. At this position, the connecting rod of the engine experience a force of N on thecrank pin at B.

Find its a horizontal and vertical component b component along BC and normal to it. Resultant of two vectors can be obtained by solving the triangle of forces. Explain the following terms: i Space ii Continuum iii Particle iv Rigid body. State and explain parallelogram law of vectors. State parallelogram law of vector and derive triangle and polygonal law of vectors.

The resultant of two forces one of which is 3 times the other is N. When the direction ofsmaller force is reversed, the resultant is N. Determine the two forces and the angle betweenthem. The gravitational acceleration is 9. Determine the instantaneousacceleration of the rocket when it was fired. Law of transmissibility 3.

Parallelogram law of forces 4. Principles of physical independence 5. Principles of superposition.

Consider the two bodies incontact with each other. Let one body apply a force F on another.

Engineering Mechanics

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